[RESOLVED] PHP Month Dropdown

TheCase

Hi,

Im trying to create a dropdown that will list the next 2 months I got this so far

      $i = date("n");
      $ii = $i + 2;
      while ($i < $ii)
          {
          echo "<option value='$i'>$i</option>";
          ++$i;
          }

The problem is I want it to loop back to 1 when it gets passed 12 how can I do this

Thanks

dalecosp

Would [man]strtotime()[/man] help?

$next=date('n',strtotime('+1 month'));
$last=date('n',strtotime('+2 months'));

$list=array(date('n'),$next,$last);
foreach ($list as $i) {
   echo "<option value='$i'>$i</option>"; 
}

dalecosp

And you might wanna test if my code's month safe (e.g., what would happen if the date of execution was December 30 or 31 ... would it still be "12,1,2" or would '+2 months' give you March 1st or 2nd, etc.)

TheCase

This seems to be ok. Thanks

dalecosp

You're welcome, of course. 🙂

But did you check for date safety? ...

Nvm, I just did. You may have troubles in December and January.

Hmm.....

TheCase

Hi,

In December I get 12,1,3 it misses out the 2nd month. Any ideas

bradgrafelman

That's because today's date is December 29th, so +1 month would be January 29th, and +2 months would be February 29th, which doesn't exist in 2011. Instead, 29 days beyond the 1st day in February 2011 is March 1st, thus why you're getting a "3" there.

Instead, I would suggest using [man]mktime/man to explicitly specify the first day of the month, e.g.:

$list = array(date('n'));
$list[]=date('n', mktime(0, 0, 0, $list[0]+1, 1)); 
$list[]=date('n', mktime(0, 0, 0, $list[0]+2, 1)); 

foreach ($list as $i) { 
   echo "<option value='$i'>$i</option>"; 
}

TheCase

Great. Thanks alot