Calulating years, months, days, since...

[mrbaseball34]

I've got this code to show how many days a person has joined our site.
(Note: users_joindate column is date type stored as '2010-02-01' in database)

  $startDate  = $res_user['users_joindate'];
  $endDate    = date('Y-m-d');
  $startArry  = date_parse($startDate);
  $endArry    = date_parse($endDate);
  $start_date = gregoriantojd($startArry['month'], $startArry['day'], $startArry['year']);
  $end_date   = gregoriantojd($endArry['month'],   $endArry['day'],   $endArry['year']);
  echo $res_user['users_fullname']." joined ".round(($end_date - $start_date), 0)." days ago.";

If MrBaseball34 joined the site on Feb 01, 2010 it says something like this:
MrBaseball34 joined 295 days ago.

I'd like it to say:
Mr Baseball joined 8 months, 22 days ago. (I think that is correct ;-))

How would I do this?

[aguywithathing]

$epoch = mktime( 0, 0, 0, $startArry['month'], $startArry['day'], $startArry['year'] ) -
mktime( 0, 0, 0, $endArry['month'], $endArry['day'], $endArry['year'] );

printf( "Days : %d", round( $epoch/60/60/24 ) );

printf( "Weeks: %d", round( $epoch/60/60/24/7 ) );

printf( "Months : %d", round( $epoch/60/60/24/30 ) ); // Rounded to 30 days in a month

printf( "Years : %d", round( $epoch/60/60/24/365 ) );

etc, note when working it out if you want months+days, floor the result and deduct it from the epoch

[mrbaseball34]

Actually ended up doing this.

  $after    = new DateTime(date("Y-m-d"));
  $before   = new DateTime($res_user['users_joindate']);
  $interval = $after->diff($before);
  $y        = $interval->format('%y');
  $m        = $interval->format('%m');
  $d        = $interval->format('%d');
  $format   = ($y>0?($y>1?"$y years, ":"$y year, "):"").($m>0?($m>1?"$m months, ":"$m month, "):"").($d>0?($d>1?"$d days ":"$d day "):"");
  echo $res_user['users_fullname']." joined ".$interval->format($format." ago");

More accurate than your code.