[RESOLVED] Simple month subtraction

[phpSimon]

Hi all

I can't think of a simple way of establishing the day and month values for the end of the previous month when only providing the month number of the current month.

This is to calculate a financial year start and end from only the start month.

For example, if the start month is 7 the year end is 30/06. If the start month is 1, the year end is 31/12.

Does anyone have a neater way doing this than my example?

Thanks!

if $fyearstartmonth == '1' {
$fyearstartmonth = '13';
}

$fyearendmonth = $fyearstartmonth - 1;
$fyearendday = date ("t", mktime(0, 0, 0, $yearendmonth, 1, 2000));

[NogDog]

How about...

$startMonth = 7;
$startTs = mktime(0, 0, 0, $startMonth, 1);
$endTs = strtotime('-1 day', $startTs);
echo date('m/d', $endTs);

[phpSimon]

Works perfectly, and really elegant. Thank you!