Getting Variables from PHP IMG

spighita

I'm stuck. I need these two scripts to pass the variable to each other. How can I do this?

include('testimage.php');

echo $color;

File name testimage.php

$im=imagecreatetruecolor(500,500);

header('Content-type: image/jpeg');
$color="yellow";
$pic=imagejpeg($im);
imagedestroy($pic);

I want to output yellow.

This is a simplified version of what I need to work.

samuelcook

include('testimage.php');

global $color;
echo $color;

spighita

Unfortunately it didn't work. Thank you for your reply though.

I would like to avoid the use of $_SESSION and cookies if at all possible.

bradgrafelman

Works fine for me... quick example:

test2.php

<?php
$message = "Hello world!";
?>

test.php

<?php
include "test2.php";

echo $message;
?>

output:

Hello world!

EDIT: Also, note that this loose coupling between these two files (e.g. you're magically picking a variable out of the air that was defined in some other file) isn't a good practice (IMHO, at least).

Instead, if you have the ability to modify the second file, I would instead encompass its functionality into either classes or functions that you can instantiate/call from the parent script.

spighita

I cannot get the example to work for the php image file (testimage.php).

bradgrafelman

Do you have display_errors set to On and error_reporting set to E_ALL?

What output does [man]var_dump/man give for $color?

spighita

I tried this and all I get is a black square box

error_reporting(E_ALL);
include('testimage.php');
var_dump($color);

bradgrafelman

Well that makes sense - your 'testimage.php' script is sending a Content-type header of an image, so your browser is attempting to parse the data as binary and render it as an image.

spighita

Is there another alternative to make this work?