I've been running into this issue
Parse error: syntax error, unexpected T_VARIABLE on line 24
I've done the normal bug checking methods I've been taught but just can not find what the issue is. Perhaps someone elses eye can spot what I can't.
<?php
$con = mysql_connect("[REMOVED FOR SECURITY]");
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
mysql_select_db("James", $con);
$sql = "CREATE TABLE Test (username varchar(15), balance int,)";
// Execute query
mysql_query($sql,$con);
mysql_query("INSERT INTO Persons (username, balance)
VALUES ('Jesse', '50')");
$userVar = 'Jesse'
//$rewardVar = 50
$originalBalance = mysql_query("SELECT balance FROM Test WHERE username = $userVar") or print ("Error Log.<br />" . $sql . "<br />" . mysql_error());
$newBalance = $originalBalance + 50;
mysql_query("UPDATE Test SET balance=$newBalance WHERE username=$userVar");
mysql_close($con);
?>