Need help with login info for php

[Megamcclenaghan]

Hi im new to using php and ive tried makeing a login page but hen i enter the details to log i get this message

"Parse error: syntax error, unexpected T_VARIABLE in C:\xampp\htdocs\Learningphp\Login.php on line 15"

Ive attached a copy of the format and the Red text is line 15

any help would be awesome

[dagon]

please post code on board, never in a word document, word may chose to reformat the quotes breaking it. I really hope you don't write your code in word.

the problem

     $get = mysql_query("SELECT count(id) FROM login WHERE User_Name="$username" and Password="$Password"");   

if your encapsulating your sting in double quotes, you want to use single quotes around the vars for the query.

Also watch the case, password and Password are not the same

[arup_senapati]

Try the following

<?php 
$username = $_POST["username"];
$password = $_POST["password"];
$login = $_GET["login"];

if ($login=="yes") {
    $con = mysql_connect("localhost","root","");
    mysql_select_db("Login");

$get = mysql_query("SELECT count(id) FROM login WHERE User_Name='".$username."' and Password='".$Password."'");   
$result = mysql_result($get, 0);

if ($result!=1) {
	echo "Invalid login.";
}elese {
	echo "login succesfull.";
 	$_session["username"] = $username;
}
}
?>