i want, if the variable $whatever is supplied instead of another one (like a checklist for example), to print the message "invalid argument". how do i do this? just theoretically.
is it
<?php if ($whatever): print "invalid argument"; ?>
[man]isset/man?
Not sure what else to suggest - perhaps you should show us some example code of the scenario you're describing, as I don't know that I understand what you're asking.