[RESOLVED] Var issues inside a function...

[tkruise]

How come I can't use there vars like these inside a function? Isn't the code right? 🙁

<?php

$datetoday=date('j, F, Y');

function ifname($name='Willian'){
if($name=='Willian'){
echo 'Welcome Mr. $name, today is, ' . $datetoday . '. \n ' . '<br>';}
else{
echo 'You are not Willian.\n ' . '<br>' . 'Logged out';
}
                                 }
?>		  

[laserlight]

For starters, you should format the code properly, e.g.,

<?php

$datetoday = date('j, F, Y');

function ifname($name = 'Willian') {
    if ($name == 'Willian') {
        echo 'Welcome Mr. $name, today is, ' . $datetoday . '. \n ' . '<br>';
    } else {
        echo 'You are not Willian.\n ' . '<br>' . 'Logged out';
    }
}
?>

So, $datetoday is not in the scope of the ifname function, hence you cannot access it from within the ifname function. One simple solution is to move the call of date, e.g.,

<?php

function ifname($name = 'Willian') {
    if ($name == 'Willian') {
        echo 'Welcome Mr. $name, today is, ' . date('j, F, Y') . '. \n ' . '<br>';
    } else {
        echo 'You are not Willian.\n ' . '<br>' . 'Logged out';
    }
}

You could also declare $datetoday global in ifname, but that is a poor solution in this case.

[tkruise]

laserlight;10984087 wrote:

So, $datetoday is not in the scope of the ifname function, hence you cannot access it from within the ifname function. One simple solution is to move the call of date, e.g.,

<?php

function ifname($name = 'Willian') {
    if ($name == 'Willian') {
        echo 'Welcome Mr. $name, today is, ' . date('j, F, Y') . '. \n ' . '<br>';
    } else {
        echo 'You are not Willian.\n ' . '<br>' . 'Logged out';
    }
}

You could also declare $datetoday global in ifname, but that is a poor solution in this case.

How could I do that? Just for the record..I dont know to declare two vars inside one function... would it be something like this?

<?php function ifname($name = 'Willian', $datetoday=  date('j, F, Y')){ ?>

[laserlight]

That would be declaring two parameters for the function, which is acceptable.

[tkruise]

appreciate that! TY