Warning: Invalid argument supplied for foreach()

[funkymonkey]

Hello, I keep receiving this error:

Warning: Invalid argument supplied for foreach()

Does anyone knows what this means?

[bradgrafelman]

It means the argument you supplied to [man]foreach/man was invalid.

Since the manual states that foreach() expects an array as the only argument, that means you supplied foreach() with something other than an array.

[funkymonkey]

bradgrafelman;10984768 wrote:

It means the argument you supplied to [man]foreach/man was invalid.

Since the manual states that foreach() expects an array as the only argument, that means you supplied foreach() with something other than an array.

Here is my code, can you help me correct the issue?

$partnerspresentation_array = $_POST['partnerspresentation'];
foreach ($partnerspresentation_array as $one_partnerspresentation) {
$sourcepresentation .= $one_partnerspresentation.",";
}
$partnerspresentation = substr($sourcepresentation, 0, -2);

$partnersorientation_array=$_POST['partnersorientation'];
foreach ($partnersorientation_array as $one_partnersorientation) {
$sourceorientation .= $one_partnersorientation.",";
}
$partnersorientation = substr($sourceorientation, 0, -2);

$partnersgender_array=$_POST['partnersgender'];
foreach ($partnersgender_array as $one_partnersgendername) {
$sourcegender .=$one_partnersgender.",";
}
$partnersgender =substr($sourcegender, 0, -2);


$partnersage_array=$_POST['partnersage'];
foreach ($partnersage_array as $one_partnersage) {
$sourceage .=$one_partnersage.",";
}
$partnersage =substr($souceage, 0, -2);

$partnersethnicity_array=$_POST['partnersethnicity'];
foreach ($partnersethnicity_array as $one_partnersethnicity) {
$sourceethnicity .=$one_partnersethnicity.",";
}
$partnersethnicity =substr($sourceethnicity, 0, -2);

$partneradjectives_array=$_POST['partneradjectives'];
foreach ($partneradjectives_array as $one_partneradjectives) {
$sourceadjective .=$one_partneradjectives.",";
}
$partneradjectives =substr($sourceadjectives, 0, -2);


$sqlClientInfo= "INSERT INTO `Client_Info` (Last_Name, First_Name, Middle_Name, Date_of_Birth, Street_Address, City, State, Zip_Code, Phone_Number, Email, Preferred_Contact, Gender, Sexual_Orientation, Race_Ethnicity, 
Gender_Presentation, Body_Type, Height, Weight, Felony, Partners_Gender, Partners_Sexual_Orientation, 
Partners_Race_Ethnicity, Partners_Gender_Presentation, Partners_Body_Type, Partners_Age, Partners_Height, Turn_On, Turn_Off, Celebrity_Crush, First_thing_you_notice, Deal_Breaker)
VALUES ('$_POST[lastname]','$_POST[firstname]','$_POST[middlename]','$_POST[birthdate]',
'$_POST[streetaddress]','$_POST[city]','$_POST[state]','$_POST[zip]','$_POST[phone]',
'$_POST[email]','$_POST[contactmethod]','$_POST[yourgender]','$_POST[yourorientation]',
'$_POST[ethnicity]','$_POST[yourpresentation]','$_POST[bodytype]','$_POST[height]',
'$_POST[weight]','$_POST[felony]','$partnersgender','$partnersorientation',
'$partnerethnicity','$partnerspresentation','$partnerbodytype',
'$partnersage','$_POST[partnersheight]','$_POST[turnon]','$_POST[turnoff]',
'$_POST[celebritycrush]','$_POST[firstthing]','$_POST[dealbreaker]')";

[leatherback]

I might be mistaken, but is this:

$partnerspresentation_array = $_POST['partnerspresentation'];
foreach ($partnerspresentation_array as $one_partnerspresentation) {
$sourcepresentation .= $one_partnerspresentation.",";
}
$partnerspresentation = substr($sourcepresentation, 0, -2); 

not easier done like this:

$partnerspresentation = implode( ', ', $_POST['partnerspresentation']);

Note however that you need to add some verification to the data which you receive from forms etc. Read up on sql injects