[RESOLVED] A question about passing variables with include()

NyteHunter

HI there I am working on a site that has an include() that needs to have a variable passed through it I was wondering if there is any way to do this.

<?php
$pageNum = 2;

include ("../header.php");
?>

when I check the variable number on the page this code comes from it is two, but when I do the same check on the included header.php $pageNum =1

So I am wondering is there any way to pass the $pageNum into the include(..header.php)

laserlight

NyteHunter wrote:
when I check the variable number on the page this code comes from it is two, but when I do the same check on the included header.php $pageNum =1

You probably assigned to $pageNum in header.php, otherwise you should also be getting 2 there.

Derokorian

If you can't find the problem from laserlight's response please post your header.php code and we will have a look see =D

bradgrafelman

I would also suggest changing header.php so that it doesn't have this "hidden dependency" on a global variable that is defined elsewhere.

Wrap the header statements in a function, and make the $pageNum variable a parameter of that function. That way the dependency is clear, since you'd do something like:

get_header($_GET['page']);

NyteHunter

Here is the header page code. I apologize ahead of time for it being clunky in coding, I plan to streamline it I just wanted to get it up and running first

from that very first print like it says $pageNum is 1

<?php
print(" the page number is $pageNum");?>
<?php
if ($pageNum = 1){
print ("<body>
<table width=\"100%\" border=\"0\" cellpadding=\"0\" cellspacing=\"0\">
<tr>
<td width=\"9%\" rowspan=\"3\" align=\"left\" valign=\"top\"><img src=\"images/brush.jpg\" width=\"168\" height=\"141\" align=\"right\" /></td>
<td width=\"6%\"><img src=\"images/pipe.gif\" width=\"63\" height=\"31\" /></td>
<td width=\"66%\" align=\"left\" valign=\"bottom\"><img src=\"images/dds.jpg\" width=\"578\" height=\"78\" align=\"bottom\" /></td>");
include("preview.php");
print(" </tr>");
}else{
print ("<body>
<table width=\"100%\" border=\"0\" cellpadding=\"0\" cellspacing=\"0\">
<tr>
<td width=\"9%\" rowspan=\"3\" align=\"left\" valign=\"top\"><img src=\"../images/brush.jpg\" width=\"168\" height=\"141\" align=\"right\" /></td>
<td width=\"6%\"><img src=\"../images/pipe.gif\" width=\"63\" height=\"31\" /></td>
<td width=\"66%\" align=\"left\" valign=\"bottom\"><img src=\"../images/dds.jpg\" width=\"578\" height=\"78\" align=\"bottom\" /></td>");
include("../preview.php");
print(" </tr>");}

Derokorian

First thing I notice is:

if ($pageNum = 1){

// should be

if ($pageNum == 1){

Notice the double equals, this is a comparison operator. With a single equals it becomes an assignment operator which means. If I $pageNum is successfully set to 1 then do this, instead of saying If $pageNum is equal to 1.

HTH

NyteHunter

bradgrafelman

I am very new to working with php so though I get what your saying I am not sure what the full code would look like that I would need to use

NyteHunter

Derokorian will change those now, thanks for telling me. lol I am very new to php so a lot of things kinda slip past me