[RESOLVED] PHP to pull file locations with soundmanager2

[perpetualwombat]

Hello I am stumped with this. I read that this can be done and I believe it is used on this example: http://www.schillmania.com/projects/soundmanager2/demo/play-mp3-links/

I am trying to make links like this:

<a type="audio/mpeg" href="/songref.php?fileID=1"></a>

pull the actual file path from this code:

$file_id = $_GET[“fileID”];

$audio=array(
'1' => 'song01.mp3',
'2' => 'song02.mp3',
'3' => 'song03.mp3',
'4' => 'song01.mp3',
'5' => 'song02.mp3'

);



$file = '/mp3/$audio[$file_id]';


if (file_exists($file)) {
    header('Content-Description: File Transfer');
    header('Content-Type: application/octet-stream');
    header('Content-Disposition: attachment; filename='.basename($file));
    header('Content-Transfer-Encoding: binary');
    header('Expires: 0');
    header('Cache-Control: must-revalidate, post-check=0, pre-check=0');
    header('Pragma: public');
    header('Content-Length: ' . filesize($file));
    ob_clean();
    flush();
    readfile($file);
    exit;
}

I got this code from a friend who found it on a site but I cannot find the source and he doesn't know either. Any help is greatly appreciated. Thank you.

[bradgrafelman]

For one, the code you posted above won't even parse correctly due to this line:

$file_id = $_GET[“fileID”];

(which contains curly quotes rather than regular double quotes).

Otherwise, the only problem I immediately see with that code is this:

$file = '/mp3/$audio[$file_id]';

First, since the filepath begins with '/mp3', that's suggesting that there is a folder called "mp3" in the root of the server's hard drive (not the root of your website - remember, URLs and such have no direct correlation with the server's filesystem!). If you want to use an absolute path that begins at the root of your website, consider using $_SERVER['DOCUMENT_ROOT']. Otherwise, use a relative path.

Second, variable interpolation is not done inside of strings delimited with single quotes. Simple example explains it all:

$msg = 'world';
echo 'Hello $msg!'; // output: Hello $msg!
echo "Hello $msg!"; // output: Hello world!

[perpetualwombat]

Thanks for the help bradgrafelman but I'm affraid this is a little over my head. I'm an amateur web programmer and I'm very new to php. Is what you're saying the file_id section should be

$file_id = $_GET[''fileID'']; 

and the file should be defined as something more like this?

$file = $_SERVER['DOCUMENT_ROOT'] . '/mp3/$audio[$file_id]'; 

I made those changes and am still running into problems with:
Parse error: syntax error, unexpected T_STRING, expecting ']' in /home/user/site.com/songref.php on line 2

Thanks for the help

[bradgrafelman]

perpetualwombat;10987669 wrote:

Is what you're saying the file_id section should be

$file_id = $_GET[''fileID'']; 

No... strings are delimited by quotes, either by a single quote or a double quote on both sides. Not two single quotes (which is instead the empty string).

perpetualwombat;10987669 wrote:

and the file should be defined as something more like this?

$file = $_SERVER['DOCUMENT_ROOT'] . '/mp3/$audio[$file_id]'; 

Closer... but note you've still got the second problem I mentioned previously. PHP handles strings differently depending upon whether you've enclosed them with single quotes or double quotes.

See the manual page [man]string[/man] for more information.

[perpetualwombat]

I got it thanks so much. It took me awhile to figure out what you said so I wanted to thank you and post it in laymans terms.

Basically I had to like you said use double quotes for it to read the variables rather then just outputing $audio[file_id] which is what it was doing with single quotes, also use the $SERVER['DOCUMENT_ROOT'] to set the right directory. So here are the changes that worked for me
Updated to:

$file_id = $_GET["fileID"];

Updated to:

$file = $_SERVER['DOCUMENT_ROOT'] . "/mp3/$audio[$file_id]";

Thanks again bradgrafelman!