regex help

[fxpepper]

Hi,

can someone please assist?

I am trying to replace all li tags. I found this online which is only removing the first li tag:

function remove_li ( $menu ){
    return preg_replace( array( '#^<li[^>]*>#', '#</li>}$#' ), '', $menu );
}

how would I set it up for removing all of the li tags in this particular case? Also, what does the '#' mean? I couldn't find a reference for it online...

thanks!

[NogDog]

Try removing the "^" at the start of the first regexp and the "$" at the end of the second, as they anchor the patterns to the start and end of the string, respectively.

[fxpepper]

NogDog;10988341 wrote:

Try removing the "^" at the start of the first regexp and the "$" at the end of the second, as they anchor the patterns to the start and end of the string, respectively.

thanks NogDog - that did it!

just curious though - do you know what the # means?

[NogDog]

The "#" characters were used as the regexp delimiter. You can use most other "special" characters too, as long as they match. They are used so that you can add any desired modifiers after the closing delimiter. For example, to make it case-insensitive:

'#<li[^>]*>#i'

[fxpepper]

okay, got it..thanks again : )