Normally the XML requested will be generated as following format:

POST mm7.sh HTTP/1.0
Host: xxx.yyy.xxx.zzz
User-Agent: NuSOAP/0.7.3 (1.114)
Content-Type: multipart/related; boundary="Part1"; type=text/xml;
SOAPAction: ""
Content-Length: 1508

<?xml version="1.0" encoding="ISO-8859-7"?>...</SOAP-ENV:Envelope>

Part1

Content-Type: multipart/related; start='<123.smil>';type='application/smil'; boundary='0'

Content-ID: <mms>

How can I include the 'start' in my Content-Type header? How can I define a Content-ID to my XML request? As I understand that it is in MM7 format.

POST mm7.sh HTTP/1.0
Host: xxx.yyy.xxx.zzz
User-Agent: NuSOAP/0.7.3 (1.114)
Content-Type: multipart/related; boundary="Part1"; type=text/xml; start="12345"
SOAPAction: ""
Content-Length: 1508

Part1

Content-Type:text/xml;charset="utf-8"

Content-ID:12345

<?xml version="1.0" encoding="ISO-8859-7"?>...</SOAP-ENV:Envelope>

Part1

Content-Type: multipart/related; start='<123.smil>';type='application/smil'; boundary='0'

Content-ID: <mms>

Your help will be very much appreciated!

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