[RESOLVED] checking is_int

clairence

I'm confused why my php verification isn't working.

I am checking the field type of a mysql table, and checking that the value entered in a form matches.

if($comptype=="int" && !is_int($val)){    

			$ekey[]=$key;
			$error.="<br><b>$key</b> ($val) must be an integer\r\n";
		}

The above is returning the following for the two integer fields in my database:

field_a (5) must be an integer
field_b (12) must be an integer

how do I get this seemingly simple check to work?

bradgrafelman

Do a [man]var_dump/man on $val to get more information about it. What is the output of that function for one of the seemingly correct values?

clairence

thanks for the quick response.

they're returning as basic strings.

string(11) "onehundred" string(1) "5"

so i guess i'm stuck on a very basic html form input => php variable question.

how do i take a numeric form input and keep it as a number in php?

it's not like i've never done this before. but let's pretend it is.

Derokorian

well you could check if its a number with is_numeric and you can cast it as an int.

bradgrafelman

Derokorian's suggestion mirrors mine for the second input. Speaking of that second form input, make sure you take a look at the 'Note' at the top of the man page entry for [man]is_int/man which warns about using it with form input.

As for the first string... not sure what to suggest. There might be (and/or most likely is) some 3rd party class/library out there that can take an English phrase such as "one hundred" and convert it into the number/string 100, however I'm not aware of any.