[RESOLVED] Passing the selected value from drop down menu

[lily30]

Hi all,

So im very new to PHP as well to this forum and I need little help.

I have this drop down menu and I would like to pass the selected value on another page.

<form name="search" method="post" action="searchComp.php" >
<label for="searchbycomp"> Search by Company</label>
<select size="1" name="searchbycomp" id="searchbycomp">
<option value=" "> </option>
<?php while($row = odbc_fetch_array($res7))
{
echo "<option value='$row[company_name]'> $row[company_name] </option>";
}

                            ?>
        	      </select> 

<input type="submit" class="styled-button-1" name="searchbycomp" value="Search">

Thanks for your help!
Lily

[planetphp]

As your form is POSTing the data to searchComp.php all the values from the form will be available in the $_POST super global.

if you want the value of searchbycomp you can access it via

$searchbycomp = $_POST['searchbycomp'];

[bradgrafelman]

When posting PHP code, please use the board's [noparse]

..

[/noparse] bbcode tags as they make your code much more easier to read and analyze.

Also, note that you can find more information about how to retrieve data from external sources (such as POST'ed data from a form) from the manual: [man]variables.external[/man].