my javascript function is not triggered if i use echo command

[tamayo]

Hi, I'm displaying a html form, based in some condition some parts of the form are displayed, for examples like this:

if($xtip==1){
  echo "<td><input type='text' name='txtrefsol 'size='10' onKeyDown='enviarSalto(event, 'txtrefsol');' ></td>";
}

so, my problem is that the function enviarSalto() is not triggered, in fact, if i display the same line outside the echo function, it works; so my question is:

1. how can I trigger the function enviarsalto when i use echo function to draw the object inside the form?

best regards

[bradgrafelman]

What does the Javascript code for the enviarSalto() function look like?

Also, can you show us the HTML of the page as viewed by your browser? In the end, that's all that matters - whether it's from a static .html file or generated by a PHP script, your browser can't tell the difference. It's all just HTML data it reads and parses.

[fontener]

try

echo "<td><input type='text' name='txtrefsol 'size='10' onKeyDown=\"enviarSalto(event, 'txtrefsol');\" ></td>";

[bradgrafelman]

D'oh! Failed to notice the quote error. Good catch, fontener.