PHP Script Help- Calling Function

phpnewbs

Hi Everyone,

I am very new at PHP and really need some help with this code. All I need to do is to get the image to display, when I call the function. Can someone please help me call this function? Here is the code below:

<?php
function generateQR($url, $width = 150, $height = 150) {
        $url    = urlencode($url);
        $image  = '<img src="http://chart.apis.google.com/chart?chs='.$width.'x'.$height.'&cht=qr&chl='.$url.'" alt="QR code" width="'.$width.'" height="'.$height.'"/>';

    return $image;
}
?>

Thank you all very much!!!

bradgrafelman

Can you show us what you've tried?

phpnewbs

Thanks for the response. I just started to learn php a few days ago, and I am unsure on where exactly to begin. I am very sorry! Do you have any suggestions on how to start this? Thanks again

bradgrafelman

Er.. it's just calling a function; it's no different from when you call the built-in [man]urlencode/man function. So I guess for an example, I'd say look at your own code. 🙂

phpnewbs

Ok, thanks. I have gotten the image to appear with this code, but the url in the QR code doesn't match to the one on the current page, any suggestions? I greatly appreciate your efforts to help me.

<?php
function generateQR($url, $width = 150, $height = 150) {
$url = urlencode($url);
$image = '<img src="http://chart.apis.google.com/chart?chs='.$width.'x'.$height.'&cht=qr&chl='.$url.'" alt="QR code" width="'.$width.'" height="'.$height.'"/>';

    return $image;
}

echo generateQR("$url", 150, 150);

Derokorian

echo generateQR("$url", 150, 150);

Where is $url ever defined? If you say inside the function, then you should have a read HERE