if(in_array) with variable

[ckroon]

Hi All. Newb question for you...

This returns "Match Found"
/////
$numbers = array(1,2,3,4);

if (in_array(3,$numbers))
{
echo "Match found";
}
else
{
echo "Match not found";
}
///////

But if I want $numbers as a variable... I get Match Not Found

$get = "1,2,3,4";
$numbers = array($get);

if (in_array(3,$numbers))
{
echo "Match found";
}
else
{
echo "Match not found";
}

Any help/advice would be greatly appreciated.

[dagon]

you can't convert a string to an array just by using the array() function. In this case the easy fix is to use explode(); like so:

$get = "1,2,3,4";
$numbers = explode(',',$get);

if however you just wanted to search a string, not an array, there are multiple functions for that.

[ckroon]

Worked a treat! 🙂