Random Numbers - 2 to 9 digits.

If my user request a 2 digit random number I can do that with rand(10,99)

if the want 5 digits then rand(11111,99999)

Instead of writing 8 if statements, one of each option..
if there anyway to take the digit they enter ($rand) and generate the random number ?
Thanks

I would also suggest using mt_rand instead of rand.

adding to the list of options how about always generating 8, or what ever the max is, then use substr() to return the size required.

Dagon - I like the idea of this.. simple !

mt_rand(pow(10, $n-1), pow(10, $n)-1)

perhaps? Assuming leading zeros are unwanted.

Though the requirements are ambiguous (why is the minimum for 5 digits "11111" when the minimum for 2 is "10" and not "11")?

Hi
My 5 digit example was to generate a number between 11111 & 99999
it was just an example.

//where count is the user selected number
$count='8';
echo substr(rand(10000000,99999999),0,$count);

Mad_T wrote:
Hi
My 5 digit example was to generate a number between 11111 & 99999
it was just an example.

Yes, I know. But that doesn't answer my question. Do you mean your other example is wrong?