Stuck on an Array

[Asgardien]

Hi
I am havin a bit of a problem with arrays and am hoping some one can help me out, or point me in the right direction. I have a Array" $data" that i get from a CURL call , I am able to get the data in the first part of the array by using " echo $data['agency_branch'];" . but i cant get any data after the second array( . would be extremly gratfull for any help on this..... THANKS in Advance.
array (
'id' => '34970',
'agency_branch' => 'ELLESMERE PORT',
'house_number' => '2',
'address1' => 'Rosset street',
'address2' => '',
'town' => 'LIVERPOOL',
'county' => '',
'postcode' => 'L6 4AW',
'reference' => 'H78',
'bedrooms' => '0',
'receptions' => '0',
'max_occupancy' => '0',
'max_tenancies' => '1',

array (
),
'bullets' =>
array (
),
'images' =>
array (
0 =>
array (
'image_name' => 'https://************************.jpg',
'thumbnail_image' => 'https://*********************.jpg',
'Target'=> 'Exterior',
),
1 =>
array (
'image_name' => 'https://*********************.jpg',
'thumbnail_image' => 'https://*********************.jpg',
'Target'=> 'Exterior',
),
2 =>
array (
'image_name' => 'https://*********************.jpg',
'thumbnail_image' => 'https://*********************.jpg',
'Target'=> 'Exterior',
),
3 =>
array (
'image_name' => 'https://*********************.jpg',
'thumbnail_image' => 'https://************************.jpg',
'Target'=> 'Exterior',
),
),
'epc_location' => '',
)

[NogDog]

It might help to add some indenting and use the forum's [noparse]

...

[/noparse] tags so we can see what's going on:

array (
	'id' => '34970',
	'agency_branch' => 'ELLESMERE PORT',
	'house_number' => '2',
	'address1' => 'Rosset street',
	'address2' => '',
	'town' => 'LIVERPOOL',
	'county' => '',
	'postcode' => 'L6 4AW',
	'reference' => 'H78',
	'bedrooms' => '0',
	'receptions' => '0',
	'max_occupancy' => '0',
	'max_tenancies' => '1',
	array (),
	'bullets' => array (),
	'images' => array (
		0 => array (
			'image_name' => 'https://***************************.jpg',
			'thumbnail_image' => 'https://***************************.jpg',
			'Target'=> 'Exterior',
		),
		1 => array (
			'image_name' => 'https://***************************.jpg',
			'thumbnail_image' => 'https://***************************.jpg',
			'Target'=> 'Exterior',
		),
		2 => array (
			'image_name' => 'https://***************************.jpg',
			'thumbnail_image' => 'https://***************************.jpg',
			'Target'=> 'Exterior',
		),
		3 => array (
			'image_name' => 'https://***************************.jpg',
			'thumbnail_image' => 'https://***************************.jpg',
			'Target'=> 'Exterior',
		),
	),
	'epc_location' => '',
)

So, if you want the last thumbnail, it would be [FONT=Courier New]$data['images'][3]['thumbnail_image'][/FONT].

[Asgardien]

Thanks a lot for that NogDog ,next post i will remember the Tags.

[Asgardien]

I am using the following code to display all the images in the above array. Howerver the code returns 4 as the size of the array but only displays one image. what am i doing wrong ? probably cant see the tree for the woods.

for ($a = 0,$b = sizeof($data['images']);$a < $b;$a++)

   $value = $data['images'][$a]['image_name'];

echo "<img src='$value' title='$value' alt='$value'>";
echo $a;

[laserlight]

Note that if you don't use braces (or alternative syntax) to enclose the body of a for loop, the next statement will be taken as the body of the for loop. Hence, your code is equivalent to:

for ($a = 0, $b = sizeof($data['images']); $a < $b; $a++)
{
   $value = $data['images'][$a]['image_name'];
}
echo "<img src='$value' title='$value' alt='$value'>";
echo $a;

[Asgardien]

Thanks for the Reply Laserlight. Now that you have pointed it out, i did originally have braces in the code which i removed for some reason.
BUT
Really gratefull for your reply and help. Thanks