Help Variables.

Vinceguy1

$v1 = "test123";
$test = "1";
echo $v['$test'];

I want it to echo $v1 because $test = 1, but it just ends up outputting nothing, what should i do?

bradgrafelman

You should probably find some very basic PHP tutorials that teach you the fundamentals of the language. I say that, because you've got a few issues:

"1" is a string containing the ASCII character representing a one. This is not the same as the integer one.
$v doesn't exist in your code, even though you're trying to use an index to access something inside that variable.
See the manual page for what a [man]string[/man] is; note that "variable interpolation" does not occur within strings delimited with single quotes (but it does inside those delimited with double quotes).
Note that there's no reason to put any quotes around $test (assuming for a moment that #2 above wasn't an issue).

Vinceguy1

....Ok, but do you think there is anyway i can echo out $v1 with using whats inside $test?

bradgrafelman

You could, using what is usually referred to as "variable variables", but a better question is... Why would you want to?

If you've got a collection of values that you want to access based on a numbered index, why aren't you using an array rather than a bunch of separate variables?

Vinceguy1

Its complicated why i would want to, but can you help me learn how?

Vinceguy1

Please help, this is very important.

Vinceguy1

Nevermind i figured it out
I did
$v[1] = "test123";
$test = 1;
echo $v['$test'];

traq

Vinceguy1;11017387 wrote:
Nevermind i figured it out
I did

...not really.

// this creates a numerically indexed array, aka "what bradgrafelman said"
$v[1] = "test123"; 

// this is 1 (not "1", as brad also explained)
$test = 1; 

// this *does not* do what you describe
// (it would result in an error: "Notice: Undefined index: $test ..."
echo $v['$test'];

// if you used "double-quotes" (or, better yet, *no* quotes), like this:
echo $v[$test];
// then, you would get the expected output "test123"