Echo main Source of Variable

this code echoes $nick9 in output. but I want to echoes tom in output, what do I do before echo?

thanks

$nick9='tom';

$number=9;
$shenick='$nick'.$number;

echo $shenick;

You are probably looking to use the syntax for variable variables:

<?php
$nick9 = 'tom';

$number = 9;
$shenick = 'nick' . $number;

echo $$shenick;

But it is usually better practice to use an array.

I agree that an array approach is probably the better approach, but just to throw out a slight variation:

$nick9='tom';
$number=9;
$shenick=${"nick$number"}; // or $shenick=${'nick'.$number}
echo $shenick;

PS: Remember that variables are not interpolated within single-quoted strings.

When you use a single quote:

echo '$foo';

--- PHP thinks you want exactly that to be printed to output.

In order for the variable to be interpolated, use a double quote:

echo "$foo";

This can also work:

echo $foo;

- but the single quote means "literally print whatever is in between these marks".

dalecosp;11032523 wrote:
... - but the single quote means "literally print whatever is in between these marks".

Except for \

or \

sometimes

: )