[RESOLVED] Alternating arrays

[Mindfreek]

Hey guys, I am Freek! I am currently studying creative technology and I have to make a website in php for a project. But I am stuck now. I use the API form recipepuppy.com and I want to parse the json from the site. That is all going well, but I want to alternate three arrays. Do one of you guys know how to do that? Thanks in advance!!

Here's what I have now.

<?php

require ('core/init.php');


//$x = DB::getInstance()->query("SELECT * FROM history WHERE user_id = ?", array(6))->results();
	$i = 'onions, garlic';

$json = file_get_contents('http://www.recipepuppy.com/api/?i=' . $i);

$a = json_decode($json);

//print_r($x);
//echo '<br><br><br>';
//print_r($a);

foreach($a->results as $recipe){
	$x = str_replace('Recipe', ' ', $recipe->title);
	echo $x . '<br>';


}
	foreach($a->results as $link){
	echo $link->href .'<br>'; 
}
foreach($a->results as $image){
	"<img src =\""echo $image->thumbnail ."\" width=\"300px\"alt =\"\"/><br>"; 
}


?>

But what I want is one image, with the recipe name and link next to it. Not just three lists. I think I have to use a for -loop but how?

[Mindfreek]

SOLVED IT! Hey Guys, I solved it myself. If you want to know how, here's the code:

foreach($a->results as $recipe){ // This foreach loop gets the recipes from recipepuppy.com and displays it on the page. 
		  $image = $recipe->thumbnail;

	  if(empty($image)) {		// Check if there is an image
  echo "<img src=\"".$myImage. ' "\ width ="100px" />';
	  } else {
  echo "<img src=\"".$image. ' "\/>';

  }
		$x = str_replace('Recipe', ' ', $recipe->title);
		echo "<a href=\"".$recipe->href .' "\/><br>'; 
		echo $x . '<br>';


}

Yes, I am very new to PHP so I am actually very happy now!