IF OR Statements

chrisguk

Hi guys,

Is the correct usage for OR:


if ( $page === "essenupdate" || "essen_done" || "essen" || "voteessen"){


include(INCLUDE_DIR . "db.php");

}

bradgrafelman

No, because that is equivalent to:

if ( $page === "essenupdate" || TRUE || TRUE || TRUE )

which is, of course, equivalent to just:

if ( TRUE )

chrisguk

I suppose you can see what I am trying to achieve, I cant figure out how to make it an OR without using elseif

chrisguk

Or would this be correct



if ( $page === "essenupdate" || $page === "essen_done" || $page === "essen" || $page === "voteessen"){ 


include(INCLUDE_DIR . "db.php"); 

}

bradgrafelman

That would work. Another way which can save you a bit of typing (depending upon the number of options) is to use [man]in_array/man, e.g.:

if( in_array( $var, array( "val1", "val2", "val3", "etc." ) ) )

EDIT: Guess I should point out that you'd need to utilize the $strict parameter of in_array() if you wanted to replicate the type of equality comparison as well.