Im trying to make a simple image upload system for my website and i keep gettting this error and i dont know how to fix it! 
Here is my PHP:
<?php
$target_dir = "uploads/";
$target_file = $target_dir . basename($_FILES["fileToUpload"]["name"]);
$uploadOk = 1;
$imageFiletype = pathinfo($target_file,PATHINFO_EXTENSION);
//Check if image is real or fake
if(isset($_POST["submit"])) {
$check = getimagesize($_FILES["fileToUpload"]["tmp_name"]);
if($check !== false) {
echo "File is an image - " . $check["mime"] . ".";
$uploadOk = 1;
} else {
echo "File is not an image.";
$uploadOk = 0;
}
}
//Check if the file already exists
if (file_exists($target_file)) {
echo "Sorry, that file already exists.";
$uploadOk = 0;
}
//Check file size
if ($_FILES["fileToUpload"]["size"] > 500000) {
echo "Sorry, your file is too large.";
$uploadOk = 0;
}
//Allow certain formats
if ($imageFileType != "jpg" && $$ $imageFileType != "png" && $imageFileType != "jpeg" && $imageFileType != "gif") {
echo "Sorry, only JPG, JPEG, PNG, & GIF files."
$uploadOk = 0;
}
?>
And here is my HTML:
<!DOCTYPE html>
<html>
<body>
<form action="upload.php" method="post" enctype="multipart/form-data">
Select Image to Upload:
<input type="file" name"fileToUpload" id="fileToUpload">
<input type="submit" value="Upload Image" name="submit">
</form>
</body>
</html>
This is the error i keep getting:
Parse error: syntax error, unexpected T_VARIABLE, expecting ',' or ';' in /home/a7281998/public_html/upload.php on line 30
