[RESOLVED] Parse error: syntax error, Why is this happening???

[Thebosslady]

...I put arrows rite before line 373
Parse error: syntax error, unexpected '<' in /home/content/07/9656607/html/artist_dashboard.php on line 373

</div>
</div>

<div id="sales">
<h4>Sales</h4><span class="liner"></span>
<div class="def-block widget">
<div class="widget-content">
<?php
$sq_song="SELECT * FROM `sales` WHERE `user` = '$artist_id' AND `download` = 'Y'";
$res_song=$db->select_data($sq_song);
if(count($res_song)==0);
<strong style="color: #666;">You have not made any sales yet.</strong>; // <-------------
<?php }
else{
?>
<table class="table_audio">
<tbody>
<thead style="border-bottom: 1px solid">
<th style="font-weight: bold;text-align: left">Song Title</th>
<th style="font-weight: bold;text-align: left">Artist Name</th>
<th style="font-weight: bold">Purchase Date</th>
</thead>

<?php
if(count($res_song)>0)
{
for($i=0;$i<count($res_song);$i++)
{
$song_id = $res_song[$i]['song'];
$artist=$res_song[$i]['artist'];
$sale_date = $res_song[$i]['saleCreated'];
$sales_dt=date('m/d/Y',strtotime($sale_date));

[Weedpacket]

When posting code, please use the formatting tags described in the [thread=10235043]FAQ[/thread] to make your post easier to read.

In this case, using those tags would have alerted you to the problem right away, because you have forgotten to close the PHP block that precedes that line.

[Thebosslady]

Weedpacket;11051443 wrote:

When posting code, please use the formatting tags described in the [thread=10235043]FAQ[/thread] to make your post easier to read.

In this case, using those tags would have alerted you to the problem right away, because you have forgotten to close the PHP block that precedes that line.

Im sorry Im new to this coding forum, and coding in general So I dont know what you mean when you say close out the PHP block? How Do I do that, what am I missing?