[RESOLVED] Problems setting vars based on json result

schwim2

Hi there everyone!

I'm having two problems with some code I've written. First, it's printing the json info to screen although I don't want it to and secondly, I'm having problems retrieving the json info for setting variables.

$ipurl = "http://ipinfo.io/".$ip;

$cURL = curl_init();

curl_setopt($cURL, CURLOPT_URL, $ipurl);
curl_setopt($cURL, CURLOPT_HTTPGET, true);

curl_setopt($cURL, CURLOPT_HTTPHEADER, array(
    'Content-Type: application/json',
    'Accept: application/json'
));

$result = curl_exec($cURL);
$json = json_decode($result, true);
curl_close($cURL);


$hostname = $json[0]['hostname'];
$city = $json['city'];
$region = $json['region'];
$country = $json['country'];
$loc = $json['loc'];
$org = $json['org'];
$postcode = $json['postcode'];

So, it seems

$result = curl_exec($cURL);

is printing the json info to screen. How do I stop this?

and secondly, although I've used json_decode and have tried to set variables but although it prints to screen, trying to use $json['elementname'] leaves me with an empty variable. What do I need to do to set these?

Thanks for your time!

Derokorian

Regaring it returns to screen, you need to use the option CURLOPT_RETURNTRANSFER and set it to true as per the documentation Here.

as for getting the jason, one you'll want to validate the the curl call actually completed successfully (probably using [man]curl_info[/man] to get the return code), as well you aren't getting a json string in $result because of the return transfer.

schwim2

Thank you very much for your help, Derokorian, it seems to be working fantastically now!

Derokorian

schwim2;11058545 wrote:
Thank you very much for your help, Derokorian, it seems to be working fantastically now!

No problem, glad it worked. Now to just memorize the plethora of CURLOPT_* constants and how to use them 😛 (no really though, I just referenced my existing code, and linked in case you needed more constants hehe)