Getting Array into Bar Graph

[Local_Hero]

I'm counting folders with specific terms in them (works fine) and I want to put this into a bar graph (graph works fine) but I can't figure out how. I'm using a bar graph from chartphp.com The graph allows you to enter in information, but I want it dynamic.
Graph:

$p->data = array(array(array("2010/10",48.25),array("2011/01",238.75),array("2011/02",95.50),array("2011/03",300.50),array("2011/04",286.80),array("2011/05",400)));

My folder count data:

$dir = '../graphics/outputs'; 
$dirs = array_slice(scandir($dir), 2);
$help = array();
rsort($help);
for ($i = 0; $i < count($dirs); $i++) {
	$name = substr($dirs[$i], 11);
	if (isset($help[$name])) {
		$help[$name]++;
	} else {
		$help[$name] = 1;
	}
}
	var_dump($help);

How do I get my folder count array into the graph without having to do it manually?

Also, my rsort($help); line doesn't seem to work and I don't know why?
Thanks for any ideas.

[Weedpacket]

First of all, the easy part:

Local Hero wrote:

Also, my rsort($help); line doesn't seem to work and I don't know why?

$help = array();
rsort($help);

It's working fine. An empty array looks exactly the same after sorting as it does before sorting: empty.

For the other question, it would appear from your example that the way to put data into the graph is to assign it to the graph object's [font=monospace]data[/font] property. So, assuming that you have a graph object in [font=monospace]$p[/font], just like the example you give, then I would expect

$p->data = $help;

to do what you're describing.

[Local_Hero]

Thanks for pointing out my sort issue, I see it now. But now once I sort, my folder names are missing:

$dir = '../graphics/outputs'; 
$dirs = array_slice(scandir($dir), 2);
$help = array();
for ($i = 0; $i < count($dirs); $i++) {
	$name = substr($dirs[$i], 11);
	if (isset($help[$name])) {
		$help[$name]++;
	} else {
		$help[$name] = 1;
	}
}
rsort($help);
echo '<pre>';
	print_r($help);
echo '</pre>';

This displays: Array
(
[0] => 31
[1] => 19
[2] => 19

How do I get the folder names instead of [0]?

[dalecosp]

Try [man]arsort/man instead of rsort(). 🙂

[Local_Hero]

That was it! Thank you.
Now I have my files and counts sorted and I have to insert it into this format:

$p->data = array(array(array("2010/10",48.25),array("2011/01",238.75),array("2011/02",95.50),array("2011/03",300.50),array("2011/04",286.80),array("2011/05",400)));

Replacing the years with folder names and numbers with the count numbers.
I realize that I need to insert array("folder name", count), for each folder in the array. Every time I try to add an echo into the for loop, it crashes.

[Weedpacket]

There's no need to have an echo in the first place at this stage.

After the above loop, you have an array [font=monospace]$help[/font] where the keys are folder names and the values are counts. So what you want now is another loop to make a new array. This loop will go through [font=monospace]$help[/font] and for each element, add a new [font=monospace]array(key, value)[/font] element to the new array.

[Local_Hero]

Almost there!
I created and formatted the loop I need:

foreach($help as $key => $value) {
  echo ',array("' . $key . '",' . $value . ')';
}

But I haven't had success trying to add it into the $p->data below

$p->data = array(array(array("0",0),array("2011/01",238.75),array("2011/02",95.50),array("2011/03",300.50),array("2011/04",286.80),array("2011/05",400)));

This is the last step. I just need a nudge over the edge. Thanks for your help!

[Weedpacket]

Try actually making an array instead of just echoing a string that looks like an array.