[RESOLVED] Compare three values

[cluelessPHP]

I'm trying to compare three values randomly generated, but I can't quite seem to get it, I've tried every combination I can think of

$(document).ready(function() {

  $( "#click" ).click(function() {
    var image1 = new Array ();
    var number1 = 1 + Math.floor(Math.random() * 3);
    image1[0] = "<img src='images/ace.jpg'>";
    image1[1] = "<img src='images/king.png'>";
    image1[2] = "<img src='images/queen.png'>";

var image2 = new Array ();
var number2 = 1 + Math.floor(Math.random() * 3);
image2[0] = "<img src='images/ace.jpg'>";
image2[1] = "<img src='images/king.png'>";
image2[2] = "<img src='images/queen.png'>";

var image3 = new Array ();
var number3 = 1 + Math.floor(Math.random() * 3);
image3[0] = "<img src='images/ace.jpg'>";
image3[1] = "<img src='images/king.png'>";
image3[2] = "<img src='images/queen.png'>";

$('.one').html(image1[number1]);
$('.two').html(image2[number2]);
$('.three').html(image3[number3]);

if(number1 && number2 && number3 === number1 && number2 && number3){
  console.log("you win");
   $('.win').html("<h1>You win!!</h1>");
}
else{
  $('.win').html("<h1>Try again!!</h1>");
  console.log("You lose");
}

  });
});

[dalecosp]

if(number1 && number2 && number3 === number1 && number2 && number3)

(I wonder why I put this here).

(I wonder what I meant).

(Perhaps I was looking for an association?)

[cluelessPHP]

$( "#click" ).click(function() {
    var image1 = new Array ();
    var number1 = 1 + Math.floor(Math.random() * 3);
    var one = $(".one"),
    two = $(".two"),
    three = $(".three");
    image1[0] = "<img src='images/ace.jpg'>";
    image1[1] = "<img src='images/king.png'>";
    image1[2] = "<img src='images/queen.png'>";

$(one).html(image1[number1]);
$(two).html(image1[number1]);
$(three).html(image1[number1]);

if(one && two && three === one && two && three){
  console.log("you win");
   $('.win').html("<h1>You win!!</h1>");
}
else{
  $('.win').html("<h1>Try again!!</h1>");
  console.log("You lose");
}

Well this maybe a little less ugly, although maybe "more" wrong but back to values and searching online values and associations

nope

[Weedpacket]

Depending on what it is you're trying to compare (objects only compare identical to themselves), [font=monospace]a[/font], [font=monospace]b[/font], and [font=monospace]c[/font] are identical if [font=monospace]a === b && b === c[/font]. (Contrariwise, if [font=monospace]a[/font] and [font=monospace]b[/font] are different objects, then [font=monospace]a !== b[/font] even if they look identical, with identical properties.)

[Evoluer]

Hi cluelessPHP,
Since you are using the same set of images, it is enough if you compare number1, number2 and number 3. As weedpacket mentioned above, use if((number1==number2) && (number2==number3))

[cluelessPHP]

Oh I didn't know you could do it like that

[cluelessPHP]

Oh bugger I marked it as resolved and it doesn't work

[cluelessPHP]

 var number1 = Math.floor(Math.random() * 3); 

Like that and it works, thanks all