Running Php Standalone

Anon

HI all,
I have Php4 running on RedHat6.2, I am trying to make crons kick off Phpscripts like a perl or shell script to for cleanups in our database and system pid's. I tried
"LYNX" but the problem is the system clean doesnt happen outside the webserver due to permissions.
I have a couple of questions:
1. Can I have PHP as standalone and as a apache module running on the same machine ?
2. If I can do the above how do I go about running the Php Standalone ?

Thanx

Anon

Yes, it's possible.
I compiled PHP 4 twice, first as a CGI version and then compiled as an Apache module. I can use either way: run PHP scripts outside the web server or inside the webserver.
Steven D

Anon

I got the Php Standalone running but have a probem when running a simple phpscript

#! /usr/local/bin/php -q
<?//
echo "Hello World";
?>//

when run displays the below

PHP: Error parsing php.ini on line 158
Hello World//

The line 158 in the php.ini is
;error_prepend_string = "<font color=cc0000>" ; string to output before an error message

Anon

I see some problem in your code:
Try this:
<?php
echo "Hello World";
?>
Suppose this file is test.php.
At the command shell: #php test.php.
If you run interactively, type php -q at the command shell.
In your example script, the "//" after the end tag ?> may cause problem.

Anon

Still I get the same message. Not sure what I am doing wrong.

Anon

It worked for me, typing in test.php:
#!/usr/bin/php
<?
echo "Hola\n";
?>

And runing it so:
php -q test.php

Thanks for the tip!!

Anon

Does somebody knows how to send parameters to a standalone PHP application. I think this should work:

php test.php parameter1 parameter2

but how can I read those parameter inside test.php?

Anon

To get the parameters from command line:
E.g php test.php parameter1 parameter2

Inside PHP code:
$parm1 = argv[1];
$parm2 = argv[2];

Note: This function (argv) is similar to C function.
Steven D.