Question to Content type Image and Variables

[Anon]

Hello all
I got a question about this Script:<?php
if($id) {

 // you may have to modify login information for your database server:
@MYSQL_CONNECT( "");

@mysql_select_db( "amadeus_allesrock_de");

$query =  "select bin_data,filetype from binary_data where id=$id";
$result = @MYSQL_QUERY($query);

$data = @MYSQL_RESULT($result,0, "bin_data");
$type = @MYSQL_RESULT($result,0, "filetype");
 echo "&a=";
Header(  "Content-type: $type");

echo $data;

};
?>
It reads images from a MySQL databas
So my question is it possible to give that PHP a variable like &Main=<?......?>
if I gona do this now it just came some text and no picture more
But i need to load this script with that variable.
Is there any possibility to do that?
Thanks a lot
Roseman

[Anon]

I think that you need to re-phrase your question. It's hard to understand what you are really asking.

[Anon]

So I have this script above and I want to tell this script a Variable so that I can use it in flash.
So the script should look like this
&main=<?.......?>
but that isn´t possible because I have a header called Content-type: image/jpeg
so I get only chars no picture
my Question now is if there is a other way to get this variable in front of a picture
so that i can call it in flash like getdata.php3?id=1 and the textfield in Flash has the variable main.
I hope somone understood me
Thanks a lot
Rose