parsing out .jpg file from remote webpage

[Anon]

I'm wondering if there is any way to grab a .jpg file from a remote html page.

I know all about using passthru, and I know that php can open remote files via ftp, and http, but how does one ignore everything except the image you want to retrieve?

Thanks in advance...

-Chris Simmons
www.peitourism.com

[Anon]

This is probably not the simplest way to do it, but:
<?
$page=implode("\n", file($webpage));
$page1=explode("src=", $page);
for($i=0; $i<count($page1); $i++)
{
$page2=explode(">", $page1[$i]);
$image[$i]=$page2[0];
}

?>
Then the $image array would (probably) have the link for all the images on the page.
Like I said, not simple, not really pretty. And you'll end up possibly having extra stuff, like height and width attributes. It depends on how the code is written.
Isn't there a way to get an array of images on a web page?

Good luck.

[Anon]

Hmm...

Your code looks good, but I think I didn't fully explain myself as to what my objective was.

I'll try again.

I have a website, it's a pretty little website, growing, strong.. good bones and hair.

I want to use an image file (islandcam.jpg) from another website (peiplay.com) and place it onto my little website.. nothing too extravagent.

The image -used- to be referenced in such a way as: "domain.com/islandcam/islandcam.jpg" and was easily accessed on any webpage in the world.. Until monday.

Of course, the owners decided to be smart (as the great Homer says it, "s-m-r-t"), and changed their image access in such a way that it requires a php file to retrieve the .jpg file. I suspect that the php file is performing a comparison on HTTP_referrer or some such, and is ignoring all that are not local to the webserver.

My question is this: How does one retrieve a webpage, with all the contents therein, and extract an image from the resulting page?

I thank you all very much for your time, in advance.

-Chris Simmons
www.peitourism.com

Anna Koop wrote:

This is probably not the simplest way to do it, but:
<?
$page=implode("\n", file($webpage));
$page1=explode("src=", $page);
for($i=0; $i<count($page1); $i++)
{
$page2=explode(">", $page1[$i]);
$image[$i]=$page2[0];
}

?>
Then the $image array would (probably) have the link for all the images on the page.
Like I said, not simple, not really pretty. And you'll end up possibly having extra stuff, like height and width attributes. It depends on how the code is written.
Isn't there a way to get an array of images on a web page?

Good luck.

[Anon]

<?
Hi cris.. if you get the url of the image them you cant grab it directly using this script.

<?
// $mref is the image url that you need grab
$file=basename($mref);
$pieces=explode(\".\",$file);

if ($pieces[1]==\"gif\") {
header (\"Content-type: image/gif\");
} else {
header (\"Content-type: image/jpeg\");
}
if ($rF=fopen($place, \"rb\")) {
fpassthru($rF);
fclose($rF);
}
?>