getting url address

[Anon]

how can i get the url from the location and only take the word in between the www. and .com,and echo it out?
eg. the url is www.phpbuilder.com and it should echo out to display only phpbulider.

thanks
frm patrilia

[Anon]

Start by looking at this : http://www.php.net/manual/function.parse-url.php

<?php
$url=parse_url("http://www.phpbuilder.com/directory/file.php3?name=Patrilia");

// here's what you need!
$host = $url["host"];

$first = strpos($host, ".");
$last = strpos($host, ".");
$length = strlen($host);

$result = substr($host, $first, $length-$last
);

echo "Result = |$result|<br>\n";
?>

That ought to be it, it might contain some errors or make some incorrect results, but it's the idea that counts. And please! Look into how the functions I've used actually work and you might learn something truly basic (that I have't learned yet!?)

Happy coding!

[Anon]

Another method is to use the explode() function:

http://www.php.net/manual/function.explode.php

for example:

<?php

 // parse a URL into an array                            $url=parse_url("http://www.phpbuilder.com/directory/file.php3?name=Patrilia"); 

// grab the host fragment

$host = $url["host"];

// explode the hostname into little tiny bits🙂
$foo = explode(".", $host);

// $foo is now an array where the second array element is equal to 'phpbuilder'
echo $foo[1];

?>

Hope this helps!!!

Cheers,

Geoff A. Virgo