help!!! if (!$submit) problem with image button

[Anon]

Hi there,

I have started using PHP4 recently and I just made my own form today which interacts with my MySQL database... anyway. I want to use an image button to submit the form and I was was using: if (!$submit) to check that the form had been sent before processing it on the same page of code. The problem is that the form just refreshes when I click my button and doesnt submit to the database at all. I tried changing the code to: if (!$image)- but it didnt work.

I hope someone can help!
Thanks

Lauren :o)

[Anon]

When you use an image to submit a form, PHP creates two variables, $inputName_x and $inputName_y, so you can use the input button as a form of image map. You should check for the existance of one or both of these variables instead of simply $inputName. If you change the method to GET, you'll see this clearly.

adam

[Anon]

I'm having the same problem with if(!$submit). Can you write down an example so i'll be a little clear on this.
Thank you

[Anon]

Change (!$submit) to (!$submit.x) or (!$submit.y). it works!

[Anon]

Actually it's (!$submit_x) because PHP converts the dot into underscore.