Getting Rid of AUTH Pop-Up Box

Anon

I don't think it's possible, but I'm not sure. Is it possible to use PHPAuth, but use your own input fields for login and password, and not that dreaded Pop-up-box-thing?

Jeroen

Anon

Use basic authentication then ...

<?
$ip = "1.2.3.4"; // proxy IP, change this according to your proxy setting in your IE or NS
$port = 1234; // proxy port, change this according to your proxy setting in your IE or NS

$fp = fsockopen($ip,$port); // connect to proxy

$login = "Scott"; // login name
$passwd = "Tiger"; // password

fputs($fp, "GET http://www.yahoo.com/ HTTP/1.1\r\nHost:www.yahoo.com:80\r\nAuthorization: Basic ".base64_encode("$login:$passwd") ."\r\n\r\n");

$data="";
while (!feof($fp)) $data.=fgets($fp,1000);
fclose($fp);

print $data;
?>

Just provide the interface to fill $login and $passwd, and it wont disturb with pop-up ...

Btw, there's no way to replace the pop-up window with your own window except you ask microsoft or sun to do that 🙂

Alex

Anon

Okay,

So I\'ve got a little form:

<form action=\'logon.php\'>
login <input type=\'text\' name=\'login\'><br>
passwd <input type=\'password\' name=\'passwd\'><br>
<input type=\'submit\'>
</form>

That gets the password. When they click \'submit\', they get to \'logon.php\' which has the following code on top:

<?
$host = \"www.jeropolis.com\"; // I don\'t use proxy... according to PHPManual you can use this too?
$port = 80;

 $fp = fsockopen($host, $port);

 fputs($fp, \"GET http://www.jeropolis.com/phpadmin/index.php3 HTTP/1.1\\r\\nHost:www.jeropolis.com:80\\r\\nAuthorization: Basic \".base64_encode(\"$login:$passwd\") .\"\\r\\n\\r\\n\"); 

 $data=\"\"; 
 while (!feof($fp)) $data.=fgets($fp,1000); 
 fclose($fp); 

 print $data;

It displays the following result :

HTTP/1.1 200 OK Date: Thu, 30 Nov 2000 12:28:35 GMT Server: Apache/1.3.12 X-Powered-By: PHP/4.0.0 Transfer-Encoding: chunked Content-Type: text/html 12c 0

In stead of the content of : http://www.jeropolis.com/phpadmin/index.php3

Anon

Okay,

So I've got a little form:

<form action='logon.php'>
login <input type='text' name='login'><br>
passwd <input type='password' name='passwd'><br>
<input type='submit'>
</form>

That gets the password. When they click 'submit', they get to 'logon.php' which has the following code on top:

<?
$host = "www.jeropolis.com"; // I don't use proxy... according to PHPManual you can use this too?
$port = 80;

$fp = fsockopen($host, $port);

fputs($fp, "GET http://www.jeropolis.com/phpadmin/index.php3
HTTP/1.1\r\nHost:www.jeropolis.com:80\r\nAuthorization: Basic ".base64_encode("$login:$passwd")
."\r\n\r\n");

$data="";
while (!feof($fp)) $data.=fgets($fp,1000);
fclose($fp);

print $data;
?>

It displays the following result :

HTTP/1.1 200 OK Date: Thu, 30 Nov 2000 12:28:35 GMT Server: Apache/1.3.12 X-Powered-By: PHP/4.0.0 Transfer-Encoding:
chunked Content-Type: text/html 12c 0

In stead of the content of : http://www.jeropolis.com/phpadmin/index.php3

Anon

Hey pal, no need to put \ in each " or ', it makes your comment and code unreadable 🙂
And we both in very different area, so when you're afternoon, I'm midnight sleeping ... ok ?

Btw, what you have done works perfectly, please see the part of header you've got :

HTTP/1.1 200 OK

It means u successfully get the HTTP response ...
Now, add this to eliminate HTTP response header ...

...
...
...

$data="";
while (!feof($fp)) $data.=fgets($fp,1000);
fclose($fp);

// Eliminate the HTTP response header
$pos=0;
for ($i=0;$i<2000;$i++) if (substr($data,$i,4)=="\r\n\r\n")
{ $pos=$i+4; $i=2000; }
$data=substr($data,$pos);

print $data;
?>

That will do ... Ok ?

Alexander Yanuar K.
SYSTEM DEVELOPER
www.globalsources.com