thats wrong with my regex? (simple?)

[Anon]

I got a string with lots of data, that looks like this:

$fellista=
<A HREF='javascript: top.s.add("Hoyo R-560 Home Theatre Surroundsystem", "HOHY1500", 1276.00, 13.00
much, much more

I got a reg ex that looks like this:
ereg("."(.)", "(.)", (.), ", $fetlista, $matches);

How do I do to get all regex matching my reg ex code example?

And how do I get the 1276.00 in my regex?

cheerS!

//Jonas

[[deleted]]

If the format of the $fellista is always the same, then why not just split it on comma, and take the 3rd element from the result?

[Anon]

Sorry I was a bit unclear in my description of the problem.
$fellista is changing all the time, adding new elements and so on. There are also more data that looks different compared with the data I showed in my example.

//Jonas

vincent wrote:

If the format of the $fellista is always the same, then why not just split it on comma, and take the 3rd element from the result?

[[deleted]]

So $fellista is completely different every time?
If there is no point to refer to, you can't get anything out reliably.
If the string allways had four comma's and the data after the 3rd comma was what you need, the it would be simple.

[Anon]

ereg("."(.)", "(.)", (.), ")
First of all, you see the " in the middle? All of those need to be escaped or you'll get a parse error. I prefer preg_match (same concept) lets take a look at that:

preg_match("/.?\"(.)?\", \"(.)?\", (.)?, /", $string, $matches);

Note first that I escaped all of the " with backslashes, to make them parse correctly. Next, I put a question mark after any ., reason being is that it turns it "non-greedy". If you just use ., it will match everything in the string, and you will not get what you are looking for. This tells it "Match only what you need".

Well, I hope that helps.

Chris King

[Anon]

Hi and thanks for your help!
It really glad for your help.
One more question
how do I print all matches?
There are many rows matching the expresion, how do I get out all rows matching the expression?

//jonas

Chris King wrote:

ereg("."(.)", "(.)", (.), ")
First of all, you see the " in the middle? All of those need to be escaped or you'll get a parse error. I prefer preg_match (same concept) lets take a look at that:

preg_match("/.?\"(.)?\", \"(.)?\", (.)?, /", $string, $matches);

Note first that I escaped all of the " with backslashes, to make them parse correctly. Next, I put a question mark after any ., reason being is that it turns it "non-greedy". If you just use ., it will match everything in the string, and you will not get what you are looking for. This tells it "Match only what you need".

Well, I hope that helps.

Chris King