passing a 'variable'? through a link

Anon

I have this link:

A STYLE="text-decoration:none;" href="sponsor.php" TARGET="_blank">Schiller International University</a></font>

Along with the link I want to send information telling 'sponsor.php' what listing to grab from the database:

$sname = "Schiller International University";

this in the information the query needs on the next page:

$result = mysql_query("SELECT * FROM schools WHERE name=('$sname')",$db);

This way I only have one sponsor file and through the link I tell it what info to post. How do I do this?

Thanks in advance!

Anon

You pass it in the url. See the URL to this post for example:

http://www.phpbuilder.net/forum/read.php3?num=1&id=112928&loc=0&thread=112928

This passes variables num and id and thread with the corresponding values. You may want to use urlencode() and ulrdecode() as well. See their respecitve entries in the manual.

Anon

you could you give me the exact code that will be in the link? I'm a newbie 😛

Ken wrote:

You pass it in the url. See the URL to this post for example:

http://www.phpbuilder.net/forum/read.php3?num=1&id=112928&loc=0&thread=112928

This passes variables num and id and thread with the corresponding values. You may want to use urlencode() and ulrdecode() as well. See their respecitve entries in the manual.

Anon

say I put: <A STYLE="text-decoration:none;" href="sponsor.php?id=1" TARGET="_blank">

how do I pick up the 'id=1' on sponsor.php page? In asp it would be:

request.querystring("id")

Anon

ASP smell too much !

with PHP it's auto
no need to request.querystring
just use the variable called $id
so it's: "id=$id"

Anon

HTML Page
<a href="something.php?id=1">link</a>

something.php
<?php

echo $id;

There ya go 🙂

Anon

I'm a newbie just getting started. I had the same question that Javi had. I copied Josh's sample code, but can not get this simple example to work.

I am running PHP4 on Apache 1.3.23 on WinXP machine.

Can anyone help me out?

Thanks!