1 + 1 = 11 ?

Anon

When I perform an operation like:

$variable = 1
$value = $variable + 1;

why do i get 11 instead of two?

Anon

Your variables are being added as if they are strings. One of the minor issues with typeless variables is that you can sometimes run into this problem. It'd probably work correclty if you did:

$value = 1 + $variable;

Anon

well i tried your code and it works fine.
$variable = 1;
$value = $variable + 1;
print($value);
the only thing i can think of right now is that it may be using $variable and $value as string and therefore when it adds the two you get 11. Check your code

Anon

Well, that shouldn't be a problem even when working with typeless variables. The only allowed operator for strings is '.' and this doesn't include '+'.

Rob wrote:

Your variables are being added as if they are strings. One of the minor issues with typeless variables is that you can sometimes run into this problem. It'd probably work correclty if you did:

$value = 1 + $variable;

kparker

even when working with typeless variables.

Exactly. What's more, even if you try to force the issue by writing:

  $variable = "1";
  $value = $variable + "1";
  print($value);

php still prints '2'.