include data from a variable

Anon

is there a way to include() data from a variable, without mirroring through a file?

$data is a variable with html-code, some php-functions within.

i want to include it to execute these php-functions, but "include $data" searches for a file named like the content of $data.

thanks for your help...

ame12

Assume the following:

$data = "setup.php";
include($data);

this translates to:

include("setup.php");

and assuming setup.php has the correct functions and such, it should work fine. I do this with my default colors and styles so that the user can easily create their own colors/style settings if they want.

Dave

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vincentpeace

I think you want to use the eval() function. It will evaluate the contents of a variable as php. This will cause trouble with the HTML stuff though. Otherwise you could (if absolutely necessary) write the variable to a file and include it.

Anon

eval() is definitely what you want. Be aware, though, that if your variable has HTML and PHP code in it, doing eval() will operate exactly as include() would if you were include()'ing a file--it will spit out the HTML and parse the PHP code.

If you do have HTML and PHP mixed in the same variable, you will need to do this: eval( "?> $variable" ); instead of just this: eval( $variable );

Good luck!!

Anon

You were right and you were right;

eval() was the function is searched and eval is a bit nasty.... i now have found a much better solution for my problem; something with classes.. 😉

thank you guys!