Checking existence of variable..

[rocketchef]

Hi.

I need to see if a variable exists, I guess using isset($var) somehow. My problem is that the variable name to check it against is from an array. So how do I reference the name of a variable from an array? It can't be:
if (isset($array[$i]))

because that would check the existence of the contents of the array.

Help appreciated,

BS

[[deleted]]

if (isset(${$array[$i]}))
{

yes it exists

};

[neuromancer]

You don't need a ; on a ending brace

[neuromancer]

Also, isset($$array[$i])

[[deleted]]

No, but it helps for readability

[[deleted]]

True, the notation with {} is just a little clearer, allmost like arrays 🙂

[neuromancer]

So your saying that this code is not reliable

if(1) {
print("1");
}

[neuromancer]

Maybe this would be more reliable

if(1) {
print("1");
};;;;;;;;;;;;;;;;;;;;;;;

[[deleted]]

Hey mister Neuromancer,
how about READING a post before you reply?

I said it helps for READABILITY, not RELIABILITY.