returning video content-type ...

[Anon]

can somebody plz tell me why this works :

<?
header ("Content-type: image/jpeg");
include "pic.jpg";
?>

and this doen't :

<?
header ("Content-type: video/mpeg");
include "dog3.mpg";
?>

... also tried :

<?
header ("Content-type: video/mpeg");
passthru ("cat -B var/video/isr_bil35.mpg");
?>

and

<?
header ("Content-type: video/mpeg");
readfile("var/video/isr_bil35.mpg");
?>

and still doesn't work right.

10X

[jjoske]

You have to print out the file.

Try this code:

$filename="CD1.jpg";
if($file=fopen($filename,"r")) {
header ("Content-type: image/jpeg");
while (!feof($file))
{
$data=fread($file,128);
print($data);
}

}
else {
print"unable to open $filename";
}
fclose($file);

[Anon]

Does anyone know how to determine the size (width and height) of an MPEG movie?

Thanks, bruni