array key from variable

[junebug]

i am trying to make a key from other variables in my script. i don't know if i am allowed to do this or not. but basically, this is what i am trying to do:

$p = "item";
$array[${$p.'id'}] = $value;

is the format not right or am i not allowed to do this? any help would be great.

thanks in advance

[[deleted]]

$p = "item";
$array[${$p.'id'}] = $value;

This uses variable variables.
What you are doing is filling an element of $array that is referenced by the value of a variable named $p.'id'

this would work, but I'm not sure if this is what you want:
$itemid = 1;
$value = 2;
$p = "item";
$array[${$p.'id'}] = $value;

which is the same as saying:

$itemid = 1;
$value = 2;
$array[$itemid] = $value;

now $array will look like

array(1=>2);

[junebug]

okay, so:

$p = "item";
$value = "2";

now what i want to end up with is this:

$array['itemid'] = 2;

so i do this:

$array[${$p.'id'}] = $value;

i haven't used variable variables to create a key before and i can't find anything on it in the manual. but when i take $array and break it apart the key is empty:

while($b = each($array))
{
$key = $b['key'];
$value = $v['value'];
print "$key: $value";
}

what prints is this:
: 2

there is no key present so i am curious if this is a limitation of php or if it is my error.

any help is appreciated.

btw thanks for the quick response.

[Anon]

To get a list of the keys in an array, you have to use a different syntax than that.

To see all the keys of an array, try this:

print implode(":",array_keys($arr_var));

[junebug]

i use each() for to see what key for what value. it works just fine for getting a list of the keys in an array. but, i tried the implode and it also returned blank.

[[deleted]]

--quote --
$p = "item";
$value = "2";
now what i want to end up with is this:
$array['itemid'] = 2;
so i do this:
$array[${$p.'id'}] = $value;
-- end quote --

And that's one step too far.
If you just want to create a key called 'itemid'
then you don't need variable variables at all, just contatenate the two strings:

$array[$p.'id'] = $value;

i haven't used variable variables to create a key before and i can't find > anything on it in the manual.

The section called 'variable variables' in the 'variable' chapter should help out here.

[junebug]

guess i was just trying to make things harder on myself. works beautifully. thanks for the help vincent.

[[deleted]]

Life is bitter
life is sweet
but you can't beat the smell
of my stinky feet

[Anon]

then you don't have any values stored in your array, most likely.