Display 5 items

[Anon]

I am trying to have a online used computer listing page.

can any one tell me how i can have it so if there are say 10 computers that it only shows 5 on a page. and so that you can click next to see the next 5?

can any one help me? I am new to PHP.

Thanks
J.L

[Anon]

there is an artical on how to do this in the artical section.

[Anon]

Take this code..

This code i got from some article from this site.

$limit=5; // rows to return
$numresults=mysql_query("select * from TableName where sdfsd= 'sdf'");
$numrows=mysql_num_rows($numresults);

// next determine if offset has been passed to script, if not use 0
if (empty($offset)) {
$offset=1;
}

// get results
$result=mysql_query("select * from TableName where sdfsd='sdfsd' limit $offset,$limit");

// now you can display the results returned
while ($data=mysql_fetch_array($result)) {
// include code to display results as you see fit
?>

<?php 

}

// next we need to do the links to other results

if ($offset==1) { // bypass PREV link if offset is 0
$prevoffset=$offset-20;
print "<a href=\"$PHP_SELF?offset=$prevoffset\">PREV</a> &nbsp; \n";
}

// calculate number of pages needing links
$pages=intval($numrows/$limit);

// $pages now contains int of pages needed unless there is a remainder from division
if ($numrows%$limit) {
// has remainder so add one page
$pages++;
}

for ($i=1;$i<=$pages;$i++) { // loop thru
$newoffset=$limit*($i-1);
print "<a href=\"$PHP_SELF?offset=$newoffset\">$i</a> &nbsp; \n";
}

// check to see if last page
if (!(($offset/$limit)==$pages) && $pages!=1) {
// not last page so give NEXT link
$newoffset=$offset+$limit;
print "<a href=\"$PHP_SELF?offset=$newoffset\">NEXT</a><p>\n";
}

?>

Chanderjit