A $variable in side the include-path

Anon

What is the (if any) syntax for using a variable inside the path for an included file?

A simple condition checks for a value in a string and if it's there, it includes the requested file. For example if the variable $show_me has the value "great_stuff" it will include the file "includes/great_stuff.txt" otherwise a default file will be included. It seems really simple, but I just keep getting parse errors all over the place.

"<?php
include ('includes/'$show_me'.txt');
?>" does not work.

toma42

include ('includes/' . $show_me . '.txt');

You have to concatonate the strings

Anon

the problem is....
i want to check a directory ...
09 <? chdir("d:/temp")
10 $dir="username";
11 if(is_dir($dir))
12 {
13 //code
14 }else
15 {mkdir($dir,0700);} ?>
php return a error...NO SUCH DIRECTORY OR FILE ON LINE 11 ...
my goals is to check is there a directory name "username" if there are not a directory name "username" i want to create it ..can anybody help me how i can solve this problem

thanx before that......