image as a button

[Anon]

i set up a screen that uses a gif image of a play button to start a realaudio file.
i want to use php to determine if the gif image was clicked on and then do some database processing.
i set up the html as input type =image
src="blah.gif" name="xxx"

[[deleted]]

Create a PHP script and make the button a link to that. Then have the script refer the visitor to the realaudio file. i.e.:

<a href="hit_count.php?out=ram_file"><img src="blah.gif"></a>

then in the hit_count.php file:

<?php
if ($out == "ram_file") {
your_update_code_here();
}
header("Location: http://yoursite.com/ram_file.ram");
?>

[Anon]

Hi tre,

You had given a solution for the image use as a link. If i use image as submit button than how can i recognize which button i cliked. if i am using nos. of submit buttons
as image. please let me know fast if u have that type of solution. You can directly email me at my mail address [e-mail]

regards
Umesh

[Anon]

<input type="image" src="whatever.jpg" name="yourname">

Works perfect with me.

[Anon]

The only issue is accessing the button's value, which gets passed as an x and y coordinate of where the button was clicked.

Using Dave's example

<input type="image" src="whatever.jpg" name="yourname">

In your script you can't say

if($yourname)

The form will pass to valriables in this case yourname.x and yourname.y which are where the user clicked on the image, so you could use

if($yourname.x > 0)

[dannyz]

I didn't get that...

[Anon]

What did you get?

[Anon]

is a value attribute not working? (value="clicked")

[Anon]

There is not value attribute passed with an input of type image. It doesn't pass the value it passes and x and y coordinate.