How to use the header() function to....

[Anon]

i will like to know how to use the header() function to display an image.I am working on a new non-database banner rotation system and i will like to call images like this <img src=image.phtml?id=0001> and as i have been searching on all the php sites i know i understand that i need to use the header function but as i havent used yet i dont know how to! if you can help me e-mail me to [e-mail] and i will place a link to your site in mine 🙂 thanks for reading!

[Anon]

Here are some common image types...

header("Content-type: image/gif"); // = gif
header("Content-type: image/jpeg"); // = jpg
header("Content-type: image/png"); // = png

Hope that solves your problem 😉

[Anon]

i need to know how to call it using an img tag. if i use:

header("Content-type: image/gif");

how do i print the image to the browser?

[Anon]

<?php
header("Content-type: image/gif");
//it doesn't matter if it is image/gif, image/jpeg or image/png
$imagename="bla/bla.jpg"; //name & path of img
$gettype=getimagesize($imagename);
switch ($gettype[2]){
case 1: $ext="gif"; break;
case 2: $ext="jpeg"; break;
case 3: $ext="png"; break;
}
eval("\$image=imagecreatefrom".$ext."(\"".$imagename."\");");
eval("image".$ext."(\$image);");
?>

The only problem is that you must have php with gd library installed (./configure --with-gd). However newest versions of gd DOESN'T support gif images, oldest - png! Pity for that!