Select Form Fields

[foxden]

Hopefully there is a simple answer to 'my' hard problem. I have some forms (info.php) that get filled in by users, then I have a (verify.php), if information needs to be changed, I pass the variables back into the (info.php) form, but the select fields and check box fields do not get populated. If I echo the variables, they are there, but will not fill these form fields for me.

Thanks

[hessian]

<option <? if($yourvar == $theirvar) { echo "selected"; } ?> value="yourvar">Your Var</option>

[foxden]

THANKS!!!

That is for each item in my select option list isn't it?

[amcgrath]

be careful with this solution, if the user's first value is selected, all subsequent ones will be too... a better way is
$sel = ($your_var == $their_var ? "SELECTED" : "");

then just echo $sel within the option tag...

[foxden]

believe it or not, this worked for me:

<select name=\"state\">
<option value=\"$state\">$state
<option value=\"AL\">AL
<option value=\"AK\">AK
<option value=\"AS\">AS
<option value=\"AZ\">AZ
</select>

putting that $state var outside of the first option tag worked!!! [by the way, I couldn't get the other solution working and that's why I tried that 😉 ]

-Josh

[amcgrath]

True, that definitely will work, but my example expects the states to be inarray, with a corresponding user value for their state. Say, for instance, you have an array call $states, -- $states[0] = "AL", $states[1] = "AK", etc.... and a varialbe called $user_state whihc is the state the user is in, then you could change your code to this:

echo "<select name=\"state\">";
while(list(,$st) = @each($states)) {
$sel = ($user_state == $st ? "SELECTED" : "");
echo "<option $sel value=\"$st\">$st";
}
echo "</select>";

[foxden]

I think I get it, that would help me with a multipl select field problem that I'm having. I'm very new to PHP and programming in general, struggling with the whole array concept 😉

Thanks for you help,

-Josh