Perl Regular Expression Help!

[sweahe]

Hi!

I want to search a string for this:
<a or <A after that any any string but </a> all the way to {$test}

Ex.
It should find this:
<a href="#" onclick="asdjh"><img src="{$test}"></a>

But not this:
<a href="#" onclick="asdjh">asdf</a><img src="{$test}">

Can someone help?

/Andreas

[[deleted]]

try this:
Note the SINGLE QUOTES around the pattern!

$sString = '<a href="#" onclick="asdjh"><img src="{$test}"></a>';
if (preg_match('/<a(.?){\$test}(.?)<\/a>/', $sString))
{
echo 'found<BR>';
}
else
{
echo 'not found<BR>';
}

$sString = '<a href="#" onclick="asdjh">asdf</a><img src="{$test}">';
if (preg_match('/<a(.?){\$test}(.?)<\/a>/', $sString))
{
echo 'found<BR>';
}
else
{
echo 'not found<BR>';
}

[sweahe]

Not quite as I wanted it, it should fail when running the second alternative as below:

$sString = '<a href="#" onclick="asdjh"><img src="{$test}"></a>';
echo $sString . "\n";
if (preg_match('/<a(.?){\$test}(.?)<\/a>/', $sString))
{
echo "found\n";
}
else
{
echo "not found\n";
}

$sString = '<a href="#" onclick="asdjh">asdf</a><img src="{$test}"><a href="#" onclick="asdjh">asdf</a>';
echo $sString . "\n";
if (preg_match('/<a(.?){\$test}(.?)<\/a>/', $sString))
{
echo "found\n";
}
else
{
echo "not found\n";
}

It must fail when it finds a </a> or </A> between <a and {$test}

Thank you anyway! 🙂
Andreas

vincent wrote:

try this:
Note the SINGLE QUOTES around the pattern!

$sString = '<a href="#" onclick="asdjh"><img src="{$test}"></a>';
if (preg_match('/<a(.?){\$test}(.?)<\/a>/', $sString))
{
echo 'found';
}
else
{
echo 'not found';
}

$sString = '<a href="#" onclick="asdjh">asdf</a><img src="{$test}">';
if (preg_match('/<a(.?){\$test}(.?)<\/a>/', $sString))
{
echo 'found';
}
else
{
echo 'not found';
}

[sweahe]

Why doesn't this fail??
(experimenting with ereg now)

$string2 = '<font>z<a href="test">asdf</a><font><img src="{$test}">';
$pattern = '[^z]';
if (ereg($pattern, $string2)) {
echo "FOUND";
} else {
echo "NOT FOUND";
}

[[deleted]]

Why should it fail?
The pattern just says: find something other than a 'z', the second characer already is something other than 'z' and satisfies the pattern.

It would be different if you put
'^[z]*$'

then the entire string must be 'not a z'

[sweahe]

Still learning...
OK, but if I want it to fail if it finds the string </a> or </A> between <a and {$test}??