Finding the most recent file

sol01

I have a script that grabs files and displays them. I was going by date based numbering on the files but there is a problem with that concerning the date factor. I would like to display these files based on the most recent one first. Anybody got any ideas?

TX a pile in advance

tasistro

// request directory listing with full time ordered by date
$command='ls -alct --full-time';

$output=$command;

// $output contains the listing
// first line is garbage : total ###
// second line is garbage .
// third line is garbage ..

// Fourth line has your file
// sample line would read

-rw-r--r-- 1 tazman tazman 15263 Fri Jan 11 21:53:24 2002 delphi60rc

Saludos
Gerardo

sol01

Yeah cool thats a big help....anyone have any cool tips for grabing that and stripping it down to the filename??

tasistro

Use

explode (string separator, string string [, int
limit])

something like

$my_file_info=explode(" ",$the_output_I_showed_you);

// explode string to array using spaces as separators

$my_file_info will be an array with the following data:

Array Index Data
0 -rw-r--r--

1 1
2 tazman

3 tazman

4 15263
5 Fri
6 Jan
7 11
8 21:53:24
9 2002
10 delphi60rc

Saludos
Gerardo Tasistro