Using quotes inside system command

Anon

I have a command that I use in a shell script :

lynx -dump -source "$cgi_url?CSID=73073900&CalculaDac=&Number=45454545"

result.html

I'm need translate this shell script to PHP and I don't know what happens with this command, already passed to PHP:

..................................

$lynx = "$cgi_url?CSID=73073900&CalculaDac=&Number=45454545";

system('lynx -dump -source \"$lynx\" > result.html');

..................................

Note: this command need the "quotes" around the variable $lynx.

But nothing works !
Some idea ?

Anon

Variable references are not expanded inside single-quoted strings.

What are you trying to do? Where is $cgi_url defined/assigned?

Anon

What are you trying to do?

I'm trying fill a (cgi) form with a PHP script and save the form result (an html page) for post utilization.
This is a thing that I always do, but always with a shell script ...

Where is $cgi_url defined/assigned?

This url is defined in PHP script, but I was try inform it (http://myhost.com/cgi-bin/cgiscript?blablablah...) and not work too ...